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Management Problem

In this section, we will look at the following model [2]:

\begin{displaymath}\begin{array}{rcl} \mbox{min } & \sum_{i=1}^nc_i+d_ix_i+\frac...
... \quad i=1:n,\\  & x_i: \mbox{integer},\quad i=1:n. \end{array}\end{displaymath} (3-1)

This model can be interpreted as a multi-item production and inventory management problem with a limited resource, where the $ x_i$ are called decision variables [17,20]. In general, the objective function minimizes the cost, which could be the sum of setup (ordering) costs, inventory holding costs, and purchase costs. The constraints provide the restrictions of a shared resource as well as non-shared resources. Moreover, the model represents numerous application problems based on the interpretations of the decision variables. There are at least four different applications using the model (3-1).

Let us consider the continuous relaxation of (3-1). In order to solve it as a second-order cone problem, we must ensure that (3-1) can be cast as SOCP. Let $ t=$max$ _j
\frac{1}{x_j}$. Then $ tx_j\geq 1,$ for all $ j$. We introduce a $ s$ in this inequality and rewrite it as

\begin{displaymath}
\begin{array}{rcl}
tx_j&\geq& s^2, \quad \mbox{ for all } j\\
\mbox{with }s &=& 1.
\end{array}\end{displaymath}

By using the following fact [5]:

$\displaystyle \omega^2 \leq xy,\quad x\geq 0,\quad y\geq 0 \Longleftrightarrow \left\Vert\begin{pmatrix}2\omega\cr x-y\end{pmatrix}\right\Vert \leq x+y,$ (3-2)

the previous inequality becomes

$\displaystyle \left \Vert \begin{pmatrix}2\cr t-x_j\end{pmatrix}\right\Vert \leq
t+x_j,$    for all $\displaystyle j.
$

Therefore, we can rewrite the inequalities as

$\displaystyle 2^2+(t-x_j)^2 \leq (t+x_j)^2,$    for all $\displaystyle j.
$

Next, define $ e$, $ u$,$ v$, and $ w$ as follows,

$\displaystyle e=\begin{pmatrix}1\cr
1\cr \vdots\cr 1\end{pmatrix}\in{\bf R}^n,\quad u=te+x,\quad
v=te-x,$ and $\displaystyle w=2e.
$

It is then clear that $ x=\frac{u-v}{2}$ and $ te=\frac{u+v}{2}$. Plugging this into our model, we obtain

\begin{displaymath}\begin{array}{rcl} \mbox{min}& \sum_{i=1}^n c_i+d_i(\frac{u-v...
...uad i=1:n,\\  & u_i^2 \geq v_i^2+w_i^2,\quad i=1:n. \end{array}\end{displaymath} (3-3)

In this form, the objective function and constraints, except the last $ n$ inequalities, are linear. Therefore, we can rewrite them as LP. Each of the last $ n$ constraints is a quadratic cone with $ u_i$, $ v_i$, and $ w_i$. We use the random problems described in [2] to generate test cases.

Example 1. Given $ 50\leq n \leq 200$, $ S_i\in [5,20]$, $ H_i\in [1,4]$, $ D_i\in [10,100]$, $ T_i\in [1,15]$, $ l_i, u_i \in
[8,25]$, $ i=1,\cdots,n.$ The total machine time available $ T_t$ is generated to ensure the feasibility of problems, i.e.,

$\displaystyle T_t=\sum_{i=1}^nT_i\bar{x}_i+$random positive number$\displaystyle ,$

where $ l_i\leq \bar{x}_i\leq u_i,$ for all $ i.$ In Chapter 5, we use Example 1 with $ n=50,75,100,200$ as part of our testing set.


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Next: Facility Location Problem (I) Up: Application Problems Previous: Application Problems
Hans D. Mittelmann 2003-09-10